Comments on: Calling function via void* pointer with arguments contained in std::container

By: niXman

niXman — Thu, 02 Jun 2011 08:07:47 +0000

Oh? sorry. Delete this post. I wrote it in Russian

By: Dmitry Shandyba

Dmitry Shandyba — Fri, 25 Feb 2011 09:52:58 +0000

Heh, that requires boost::fusion, while the original approach is in naked C++0x, showing the mechanics of the process!
Also, this approach doesn’t work for functions casted to void* pointers, so the following snippet doesn’t even compile:

void *pFun = reinterpret_cast(&f1); boost::fusion::invoke(pFun, boost::fusion::make_vector());

PS Anyway, surely the task should have many possible solutions, including elegant and simple ones, like the one you provided, even if they don’t match the task precisely So thanks for that!

By: niXman

niXman — Fri, 25 Feb 2011 06:36:27 +0000

All is much easier

#include
#include
#include
#include

void f1() {
std::cout << "f1()" << std::endl;
}

int f2() {
std::cout << "f2()" << std::endl;
return 3;
}

int f3(int v) {
std::cout << "f3()" << std::endl;
return f2()+v;
}

int main() {
/** without args */
boost::fusion::invoke(&f1, boost::fusion::make_vector());

/** without args */
boost::fusion::invoke(&f2, boost::fusion::make_vector());

/** with args */
int r = boost::fusion::invoke(&f3, boost::fusion::make_vector(3));
std::cout << r << std::endl;
}

http://liveworkspace.org/code/da4fb745ee9f2509eb5af862408e7648